Base | Representation |
---|---|
bin | 10001101000001110110… |
… | …111111011011110001011 |
3 | 11021210220122212112022001 |
4 | 101220032313323132023 |
5 | 124322002130220021 |
6 | 2324305020011431 |
7 | 153344241551122 |
oct | 21501667733613 |
9 | 4253818775261 |
10 | 1211430320011 |
11 | 42784591975a |
12 | 176949690b77 |
13 | 8a31170b482 |
14 | 428c2612ab9 |
15 | 217a342c091 |
hex | 11a0edfb78b |
1211430320011 has 4 divisors (see below), whose sum is σ = 1211455657152. Its totient is φ = 1211404982872.
The previous prime is 1211430319949. The next prime is 1211430320033. The reversal of 1211430320011 is 1100230341121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1211430320011 - 223 = 1211421931403 is a prime.
It is a super-3 number, since 3×12114303200113 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1211430320041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12596716 + ... + 12692521.
It is an arithmetic number, because the mean of its divisors is an integer number (302863914288).
Almost surely, 21211430320011 is an apocalyptic number.
1211430320011 is a deficient number, since it is larger than the sum of its proper divisors (25337141).
1211430320011 is an equidigital number, since it uses as much as digits as its factorization.
1211430320011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25337140.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1211430320011 its reverse (1100230341121), we get a palindrome (2311660661132).
The spelling of 1211430320011 in words is "one trillion, two hundred eleven billion, four hundred thirty million, three hundred twenty thousand, eleven".
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