1211430320041 has 2 divisors, whose sum is σ = 1211430320042. Its totient is φ = 1211430320040.

The previous prime is 1211430320033. The next prime is 1211430320129. The reversal of 1211430320041 is 1400230341121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1087264998400 + 124165321641 = 1042720^2 + 352371^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211430320041 - 2³ = 1211430320033 is a prime.

It is a super-3 number, since 3×1211430320041³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1211430319994 and 1211430320021.

It is not a weakly prime, because it can be changed into another prime (1211430620041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605715160020 + 605715160021.

It is an arithmetic number, because the mean of its divisors is an integer number (605715160021).

Almost surely, 2^{1211430320041} is an apocalyptic number.

It is an amenable number.

1211430320041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211430320041 is an equidigital number, since it uses as much as digits as its factorization.

1211430320041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1211430320041 its reverse (1400230341121), we get a palindrome (2611660661162).

The spelling of 1211430320041 in words is "one trillion, two hundred eleven billion, four hundred thirty million, three hundred twenty thousand, forty-one".