Base | Representation |
---|---|
bin | 10110100100001000… |
… | …11101101110110111 |
3 | 1011021021020020100001 |
4 | 23102010131232313 |
5 | 144302231222221 |
6 | 5322031532131 |
7 | 606130011052 |
oct | 132204355667 |
9 | 34237206301 |
10 | 12114320311 |
11 | 5157244175 |
12 | 242108a047 |
13 | 11b0a50492 |
14 | 82cc99a99 |
15 | 4ad803391 |
hex | 2d211dbb7 |
12114320311 has 4 divisors (see below), whose sum is σ = 12116386800. Its totient is φ = 12112253824.
The previous prime is 12114320299. The next prime is 12114320327. The reversal of 12114320311 is 11302341121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12114320311 is a prime.
It is a super-3 number, since 3×121143203113 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12114360311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1024426 + ... + 1036183.
It is an arithmetic number, because the mean of its divisors is an integer number (3029096700).
Almost surely, 212114320311 is an apocalyptic number.
12114320311 is a deficient number, since it is larger than the sum of its proper divisors (2066489).
12114320311 is an equidigital number, since it uses as much as digits as its factorization.
12114320311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2066488.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 12114320311 its reverse (11302341121), we get a palindrome (23416661432).
The spelling of 12114320311 in words is "twelve billion, one hundred fourteen million, three hundred twenty thousand, three hundred eleven".
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