12114323433 has 12 divisors (see below), whose sum is σ = 17499446640. Its totient is φ = 8075763576.

The previous prime is 12114323413. The next prime is 12114323527. The reversal of 12114323433 is 33432341121.

It is a happy number.

It is not a de Polignac number, because 12114323433 - 2⁵ = 12114323401 is a prime.

It is a super-3 number, since 3×12114323433³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12114323397 and 12114323406.

It is not an unprimeable number, because it can be changed into a prime (12114323413) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 238998 + ... + 285216.

It is an arithmetic number, because the mean of its divisors is an integer number (1458287220).

Almost surely, 2^12114323433 is an apocalyptic number.

It is an amenable number.

12114323433 is a deficient number, since it is larger than the sum of its proper divisors (5385123207).

12114323433 is a wasteful number, since it uses less digits than its factorization.

12114323433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75348 (or 75345 counting only the distinct ones).

The product of its digits is 5184, while the sum is 27.

Adding to 12114323433 its reverse (33432341121), we get a palindrome (45546664554).

The spelling of 12114323433 in words is "twelve billion, one hundred fourteen million, three hundred twenty-three thousand, four hundred thirty-three".