12114341441 has 4 divisors (see below), whose sum is σ = 12115666992. Its totient is φ = 12113015892.

The previous prime is 12114341413. The next prime is 12114341471. The reversal of 12114341441 is 14414341121.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12114341441 - 2⁶ = 12114341377 is a prime.

It is a super-3 number, since 3×12114341441³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12114341441.

It is not an unprimeable number, because it can be changed into a prime (12114341411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 648971 + ... + 667376.

It is an arithmetic number, because the mean of its divisors is an integer number (3028916748).

Almost surely, 2^12114341441 is an apocalyptic number.

It is an amenable number.

12114341441 is a deficient number, since it is larger than the sum of its proper divisors (1325551).

12114341441 is an equidigital number, since it uses as much as digits as its factorization.

12114341441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1325550.

The product of its digits is 1536, while the sum is 26.

Adding to 12114341441 its reverse (14414341121), we get a palindrome (26528682562).

The spelling of 12114341441 in words is "twelve billion, one hundred fourteen million, three hundred forty-one thousand, four hundred forty-one".