12114411143 has 4 divisors (see below), whose sum is σ = 12201565320. Its totient is φ = 12027256968.

The previous prime is 12114411137. The next prime is 12114411149. The reversal of 12114411143 is 34111441121.

12114411143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (12114411137) and next prime (12114411149).

It is a cyclic number.

It is not a de Polignac number, because 12114411143 - 2¹⁸ = 12114148999 is a prime.

It is a super-3 number, since 3×12114411143³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12114411149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43576880 + ... + 43577157.

It is an arithmetic number, because the mean of its divisors is an integer number (3050391330).

Almost surely, 2^12114411143 is an apocalyptic number.

12114411143 is a deficient number, since it is larger than the sum of its proper divisors (87154177).

12114411143 is an equidigital number, since it uses as much as digits as its factorization.

12114411143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87154176.

The product of its digits is 384, while the sum is 23.

Adding to 12114411143 its reverse (34111441121), we get a palindrome (46225852264).

The spelling of 12114411143 in words is "twelve billion, one hundred fourteen million, four hundred eleven thousand, one hundred forty-three".