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12114412013 = 111101310183
BaseRepresentation
bin10110100100001001…
…10100000111101101
31011021021101220010102
423102010310013231
5144302242141023
65322033520445
7606130542314
oct132204640755
934237356112
1012114412013
1151572a7060
122421113125
1311b0a83142
1482ccc127b
154ad820628
hex2d21341ed

12114412013 has 4 divisors (see below), whose sum is σ = 13215722208. Its totient is φ = 11013101820.

The previous prime is 12114411979. The next prime is 12114412043. The reversal of 12114412013 is 31021441121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31021441121 = 112820131011.

It is a cyclic number.

It is not a de Polignac number, because 12114412013 - 210 = 12114410989 is a prime.

It is a super-3 number, since 3×121144120133 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12114412043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550655081 + ... + 550655102.

It is an arithmetic number, because the mean of its divisors is an integer number (3303930552).

Almost surely, 212114412013 is an apocalyptic number.

It is an amenable number.

12114412013 is a deficient number, since it is larger than the sum of its proper divisors (1101310195).

12114412013 is a wasteful number, since it uses less digits than its factorization.

12114412013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1101310194.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 12114412013 its reverse (31021441121), we get a palindrome (43135853134).

The spelling of 12114412013 in words is "twelve billion, one hundred fourteen million, four hundred twelve thousand, thirteen".

Divisors: 1 11 1101310183 12114412013