12114446431 has 4 divisors (see below), whose sum is σ = 12114680032. Its totient is φ = 12114212832.

The previous prime is 12114446401. The next prime is 12114446441. The reversal of 12114446431 is 13464441121.

12114446431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13464441121 = 115259 ⋅116819.

It is a cyclic number.

It is not a de Polignac number, because 12114446431 - 2⁹ = 12114445919 is a prime.

It is a super-3 number, since 3×12114446431³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12114446393 and 12114446402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12114446401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231 + ... + 155656.

It is an arithmetic number, because the mean of its divisors is an integer number (3028670008).

Almost surely, 2^12114446431 is an apocalyptic number.

12114446431 is a deficient number, since it is larger than the sum of its proper divisors (233601).

12114446431 is an equidigital number, since it uses as much as digits as its factorization.

12114446431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 233600.

The product of its digits is 9216, while the sum is 31.

Adding to 12114446431 its reverse (13464441121), we get a palindrome (25578887552).

The spelling of 12114446431 in words is "twelve billion, one hundred fourteen million, four hundred forty-six thousand, four hundred thirty-one".