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12116150554423 = 18087676698569
BaseRepresentation
bin1011000001010000001011…
…0110011000111100110111
31120220021220100211121200111
42300110002312120330313
53042002334020220143
641434025511323451
72360235335310346
oct260240266307467
946807810747614
1012116150554423
113951481136543
121438236380587
1369b7182198b6
142dc5d39a1b5d
1516027ee8e99d
hexb0502d98f37

12116150554423 has 4 divisors (see below), whose sum is σ = 12116159061760. Its totient is φ = 12116142047088.

The previous prime is 12116150554393. The next prime is 12116150554427. The reversal of 12116150554423 is 32445505161121.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 12116150554423 - 225 = 12116116999991 is a prime.

It is a super-2 number, since 2×121161505544232 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12116150554427) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1540518 + ... + 5158051.

It is an arithmetic number, because the mean of its divisors is an integer number (3029039765440).

Almost surely, 212116150554423 is an apocalyptic number.

12116150554423 is a deficient number, since it is larger than the sum of its proper divisors (8507337).

12116150554423 is an equidigital number, since it uses as much as digits as its factorization.

12116150554423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8507336.

The product of its (nonzero) digits is 144000, while the sum is 40.

The spelling of 12116150554423 in words is "twelve trillion, one hundred sixteen billion, one hundred fifty million, five hundred fifty-four thousand, four hundred twenty-three".

Divisors: 1 1808767 6698569 12116150554423