Base | Representation |
---|---|
bin | 1011000001010011111010… |
… | …1100000010100000110011 |
3 | 1120220101111022220000111100 |
4 | 2300110332230002200303 |
5 | 3042011413021132120 |
6 | 41434313253015443 |
7 | 2360302245424602 |
oct | 260247654024063 |
9 | 46811438800440 |
10 | 12117154474035 |
11 | 3951946897176 |
12 | 1438476624583 |
13 | 69b8481c9b80 |
14 | 2dc68b04da39 |
15 | 1602dd197490 |
hex | b053eb02833 |
12117154474035 has 48 divisors (see below), whose sum is σ = 22619616522048. Its totient is φ = 5965123564800.
The previous prime is 12117154474021. The next prime is 12117154474067. The reversal of 12117154474035 is 53047445171121.
12117154474035 is a `hidden beast` number, since 1 + 2 + 1 + 1 + 7 + 1 + 544 + 74 + 0 + 35 = 666.
It is not a de Polignac number, because 12117154474035 - 214 = 12117154457651 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 14277505 + ... + 15102365.
It is an arithmetic number, because the mean of its divisors is an integer number (471242010876).
Almost surely, 212117154474035 is an apocalyptic number.
12117154474035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12117154474035 is a deficient number, since it is larger than the sum of its proper divisors (10502462048013).
12117154474035 is a wasteful number, since it uses less digits than its factorization.
12117154474035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 849996 (or 849993 counting only the distinct ones).
The product of its (nonzero) digits is 470400, while the sum is 45.
The spelling of 12117154474035 in words is "twelve trillion, one hundred seventeen billion, one hundred fifty-four million, four hundred seventy-four thousand, thirty-five".
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