12120034303 has 4 divisors (see below), whose sum is σ = 13052344648. Its totient is φ = 11187723960.

The previous prime is 12120034271. The next prime is 12120034387. The reversal of 12120034303 is 30343002121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30343002121 = 4241 ⋅7154681.

It is a cyclic number.

It is not a de Polignac number, because 12120034303 - 2⁵ = 12120034271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12120034103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 466155153 + ... + 466155178.

It is an arithmetic number, because the mean of its divisors is an integer number (3263086162).

Almost surely, 2^12120034303 is an apocalyptic number.

12120034303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12120034303 is a deficient number, since it is larger than the sum of its proper divisors (932310345).

12120034303 is an equidigital number, since it uses as much as digits as its factorization.

12120034303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 932310344.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 12120034303 its reverse (30343002121), we get a palindrome (42463036424).

The spelling of 12120034303 in words is "twelve billion, one hundred twenty million, thirty-four thousand, three hundred three".