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12120052015 = 510134336991
BaseRepresentation
bin10110100100110100…
…10101000100101111
31011021200000102202101
423102122111010233
5144310213131030
65322354435531
7606226512421
oct132232250457
934250012671
1012120052015
11515a4a9515
122422b92ba7
1311b1ca9316
1482d94c811
154ae0867ca
hex2d269512f

12120052015 has 16 divisors (see below), whose sum is σ = 14694443136. Its totient is φ = 9595872000.

The previous prime is 12120052013. The next prime is 12120052027. The reversal of 12120052015 is 51025002121.

12120052015 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 12120052015 - 21 = 12120052013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12120051983 and 12120052001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12120052013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1730170 + ... + 1737160.

It is an arithmetic number, because the mean of its divisors is an integer number (918402696).

Almost surely, 212120052015 is an apocalyptic number.

12120052015 is a deficient number, since it is larger than the sum of its proper divisors (2574391121).

12120052015 is a wasteful number, since it uses less digits than its factorization.

12120052015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10530.

The product of its (nonzero) digits is 200, while the sum is 19.

Adding to 12120052015 its reverse (51025002121), we get a palindrome (63145054136).

The spelling of 12120052015 in words is "twelve billion, one hundred twenty million, fifty-two thousand, fifteen".

Divisors: 1 5 101 505 3433 6991 17165 34955 346733 706091 1733665 3530455 24000103 120000515 2424010403 12120052015