Base | Representation |
---|---|
bin | 1011000001100010101100… |
… | …0111101000011101010011 |
3 | 1120220202201202212000222012 |
4 | 2300120223013220131103 |
5 | 3042043024002132243 |
6 | 41440211032133135 |
7 | 2360502452435312 |
oct | 260305307503523 |
9 | 46822652760865 |
10 | 12121121130323 |
11 | 39535a1976807 |
12 | 14391a2b371ab |
13 | 69c02ac4567a |
14 | 2dc945ba4279 |
15 | 160471532d18 |
hex | b062b1e8753 |
12121121130323 has 4 divisors (see below), whose sum is σ = 12195483836808. Its totient is φ = 12046758423840.
The previous prime is 12121121130269. The next prime is 12121121130329. The reversal of 12121121130323 is 32303112112121.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12121121130323 - 230 = 12120047388499 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12121121130329) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37181352998 + ... + 37181353323.
It is an arithmetic number, because the mean of its divisors is an integer number (3048870959202).
Almost surely, 212121121130323 is an apocalyptic number.
12121121130323 is a deficient number, since it is larger than the sum of its proper divisors (74362706485).
12121121130323 is an equidigital number, since it uses as much as digits as its factorization.
12121121130323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74362706484.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 12121121130323 its reverse (32303112112121), we get a palindrome (44424233242444).
The spelling of 12121121130323 in words is "twelve trillion, one hundred twenty-one billion, one hundred twenty-one million, one hundred thirty thousand, three hundred twenty-three".
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