Base | Representation |
---|---|
bin | 1011000001100011011011… |
… | …1110101100010010011111 |
3 | 1120220210020122021102022111 |
4 | 2300120312332230102133 |
5 | 3042043430422111221 |
6 | 41440242501054451 |
7 | 2360510416655533 |
oct | 260306676542237 |
9 | 46823218242274 |
10 | 12121320113311 |
11 | 3953694224662 |
12 | 14392396b7427 |
13 | 69c060234a96 |
14 | 2dc96439dbc3 |
15 | 160483c3abe1 |
hex | b0636fac49f |
12121320113311 has 4 divisors (see below), whose sum is σ = 12121826690800. Its totient is φ = 12120813535824.
The previous prime is 12121320113269. The next prime is 12121320113317. The reversal of 12121320113311 is 11331102312121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12121320113311 - 237 = 11983881159839 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12121320113317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 253252851 + ... + 253300708.
It is an arithmetic number, because the mean of its divisors is an integer number (3030456672700).
Almost surely, 212121320113311 is an apocalyptic number.
12121320113311 is a deficient number, since it is larger than the sum of its proper divisors (506577489).
12121320113311 is an equidigital number, since it uses as much as digits as its factorization.
12121320113311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 506577488.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 12121320113311 its reverse (11331102312121), we get a palindrome (23452422425432).
The spelling of 12121320113311 in words is "twelve trillion, one hundred twenty-one billion, three hundred twenty million, one hundred thirteen thousand, three hundred eleven".
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