Base | Representation |
---|---|
bin | 1011000001100110000001… |
… | …0001111101111010100111 |
3 | 1120220212000221010100012110 |
4 | 2300121200101331322213 |
5 | 3042101340314011403 |
6 | 41440435332452103 |
7 | 2360533532455122 |
oct | 260314021757247 |
9 | 46825027110173 |
10 | 12122013032103 |
11 | 3953a0a377817 |
12 | 14393b177a033 |
13 | 69c140964cc0 |
14 | 2dc9cc4133b9 |
15 | 1604c49b0103 |
hex | b066047dea7 |
12122013032103 has 8 divisors (see below), whose sum is σ = 17405967430768. Its totient is φ = 7459700327424.
The previous prime is 12122013031979. The next prime is 12122013032123. The reversal of 12122013032103 is 30123031022121.
12122013032103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12122013032103 - 230 = 12120939290279 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12122013032103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12122013032123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 155410423450 + ... + 155410423527.
It is an arithmetic number, because the mean of its divisors is an integer number (2175745928846).
Almost surely, 212122013032103 is an apocalyptic number.
12122013032103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12122013032103 is a deficient number, since it is larger than the sum of its proper divisors (5283954398665).
12122013032103 is a wasteful number, since it uses less digits than its factorization.
12122013032103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 310820846993.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 12122013032103 its reverse (30123031022121), we get a palindrome (42245044054224).
The spelling of 12122013032103 in words is "twelve trillion, one hundred twenty-two billion, thirteen million, thirty-two thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •