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1212221012113 = 1286839420211
BaseRepresentation
bin10001101000111110000…
…000001011100010010001
311021212221202200211221201
4101220332000023202101
5124330112034341423
62324515303151201
7153402652406656
oct21507600134221
94255852624851
101212221012113
11428111182401
12176b2a445501
138a409482817
1442959637c2d
15217eca662ad
hex11a3e00b891

1212221012113 has 4 divisors (see below), whose sum is σ = 1212230561008. Its totient is φ = 1212211463220.

The previous prime is 1212221012083. The next prime is 1212221012117. The reversal of 1212221012113 is 3112101222121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1212221012113 - 221 = 1212218914961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1212221012117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4581423 + ... + 4838788.

It is an arithmetic number, because the mean of its divisors is an integer number (303057640252).

Almost surely, 21212221012113 is an apocalyptic number.

It is an amenable number.

1212221012113 is a deficient number, since it is larger than the sum of its proper divisors (9548895).

1212221012113 is an equidigital number, since it uses as much as digits as its factorization.

1212221012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9548894.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1212221012113 its reverse (3112101222121), we get a palindrome (4324322234234).

The spelling of 1212221012113 in words is "one trillion, two hundred twelve billion, two hundred twenty-one million, twelve thousand, one hundred thirteen".

Divisors: 1 128683 9420211 1212221012113