12122242133 has 4 divisors (see below), whose sum is σ = 12122833920. Its totient is φ = 12121650348.

The previous prime is 12122242091. The next prime is 12122242147. The reversal of 12122242133 is 33124222121.

12122242133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33124222121 = 43 ⋅770330747.

It is a cyclic number.

It is not a de Polignac number, because 12122242133 - 2⁸ = 12122241877 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12122242099 and 12122242108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12122242183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 264023 + ... + 306516.

It is an arithmetic number, because the mean of its divisors is an integer number (3030708480).

Almost surely, 2^12122242133 is an apocalyptic number.

It is an amenable number.

12122242133 is a deficient number, since it is larger than the sum of its proper divisors (591787).

12122242133 is an equidigital number, since it uses as much as digits as its factorization.

12122242133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 591786.

The product of its digits is 1152, while the sum is 23.

Adding to 12122242133 its reverse (33124222121), we get a palindrome (45246464254).

The spelling of 12122242133 in words is "twelve billion, one hundred twenty-two million, two hundred forty-two thousand, one hundred thirty-three".