Base | Representation |
---|---|
bin | 10110100101000110… |
… | …11100010110011001 |
3 | 1011021211111210222111 |
4 | 23102203130112121 |
5 | 144311321103423 |
6 | 5322521552321 |
7 | 606256022626 |
oct | 132243342631 |
9 | 34254453874 |
10 | 12122441113 |
11 | 5160890482 |
12 | 24239456a1 |
13 | 11b26348a3 |
14 | 82ddb134d |
15 | 4ae3a960d |
hex | 2d28dc599 |
12122441113 has 8 divisors (see below), whose sum is σ = 12381973632. Its totient is φ = 11862975696.
The previous prime is 12122441087. The next prime is 12122441171. The reversal of 12122441113 is 31114422121.
12122441113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12122441113 - 213 = 12122432921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12122441813) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 552631 + ... + 574147.
It is an arithmetic number, because the mean of its divisors is an integer number (1547746704).
Almost surely, 212122441113 is an apocalyptic number.
It is an amenable number.
12122441113 is a deficient number, since it is larger than the sum of its proper divisors (259532519).
12122441113 is a wasteful number, since it uses less digits than its factorization.
12122441113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33551.
The product of its digits is 384, while the sum is 22.
Adding to 12122441113 its reverse (31114422121), we get a palindrome (43236863234).
The spelling of 12122441113 in words is "twelve billion, one hundred twenty-two million, four hundred forty-one thousand, one hundred thirteen".
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