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12123000143 = 56401214943
BaseRepresentation
bin10110100101001011…
…00100110101001111
31011021212120012211022
423102211210311033
5144311442001033
65322541544355
7606263541512
oct132245446517
934255505738
1012123000143
115161132491
122423b750bb
1311b279c187
148300b8d79
154ae46a098
hex2d2964d4f

12123000143 has 4 divisors (see below), whose sum is σ = 12123271488. Its totient is φ = 12122728800.

The previous prime is 12123000121. The next prime is 12123000157. The reversal of 12123000143 is 34100032121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12123000143 - 26 = 12123000079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12123000163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51071 + ... + 163872.

It is an arithmetic number, because the mean of its divisors is an integer number (3030817872).

Almost surely, 212123000143 is an apocalyptic number.

12123000143 is a deficient number, since it is larger than the sum of its proper divisors (271345).

12123000143 is an equidigital number, since it uses as much as digits as its factorization.

12123000143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 271344.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12123000143 its reverse (34100032121), we get a palindrome (46223032264).

The spelling of 12123000143 in words is "twelve billion, one hundred twenty-three million, one hundred forty-three", and thus it is an aban number.

Divisors: 1 56401 214943 12123000143