Base | Representation |
---|---|
bin | 10110100101001100… |
… | …11011010100000111 |
3 | 1011021212222112221111 |
4 | 23102212123110013 |
5 | 144312021121203 |
6 | 5322550425451 |
7 | 606265461232 |
oct | 132246332407 |
9 | 34255875844 |
10 | 12123223303 |
11 | 5161275114 |
12 | 2424062287 |
13 | 11b2849919 |
14 | 830136419 |
15 | 4ae4b126d |
hex | 2d299b507 |
12123223303 has 4 divisors (see below), whose sum is σ = 12123453528. Its totient is φ = 12122993080.
The previous prime is 12123223267. The next prime is 12123223319. The reversal of 12123223303 is 30332232121.
12123223303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12123223303 - 217 = 12123092231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12123223373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7188 + ... + 155878.
It is an arithmetic number, because the mean of its divisors is an integer number (3030863382).
Almost surely, 212123223303 is an apocalyptic number.
12123223303 is a deficient number, since it is larger than the sum of its proper divisors (230225).
12123223303 is an equidigital number, since it uses as much as digits as its factorization.
12123223303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 230224.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 12123223303 its reverse (30332232121), we get a palindrome (42455455424).
The spelling of 12123223303 in words is "twelve billion, one hundred twenty-three million, two hundred twenty-three thousand, three hundred three".
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