12123313340041 has 4 divisors (see below), whose sum is σ = 12248295951892. Its totient is φ = 11998330728192.

The previous prime is 12123313339981. The next prime is 12123313340123. The reversal of 12123313340041 is 14004331332121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3455564977225 + 8667748362816 = 1858915^2 + 2944104^2 .

It is a cyclic number.

It is not a de Polignac number, because 12123313340041 - 2³⁷ = 11985874386569 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12123313339991 and 12123313340009.

It is not an unprimeable number, because it can be changed into a prime (12123313340441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62491305780 + ... + 62491305973.

It is an arithmetic number, because the mean of its divisors is an integer number (3062073987973).

Almost surely, 2^{12123313340041} is an apocalyptic number.

It is an amenable number.

12123313340041 is a deficient number, since it is larger than the sum of its proper divisors (124982611851).

12123313340041 is an equidigital number, since it uses as much as digits as its factorization.

12123313340041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 124982611850.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 12123313340041 its reverse (14004331332121), we get a palindrome (26127644672162).

The spelling of 12123313340041 in words is "twelve trillion, one hundred twenty-three billion, three hundred thirteen million, three hundred forty thousand, forty-one".