Base | Representation |
---|---|
bin | 10001101001010000011… |
… | …010111110010010110111 |
3 | 11021220202022011100211201 |
4 | 101221100122332102313 |
5 | 124331230141310110 |
6 | 2325010102313331 |
7 | 153413424110044 |
oct | 21512032762267 |
9 | 4256668140751 |
10 | 1212530025655 |
11 | 42825a6528a3 |
12 | 176bb5a28847 |
13 | 8a4584b8180 |
14 | 429886b61cb |
15 | 21819c55b3a |
hex | 11a506be4b7 |
1212530025655 has 16 divisors (see below), whose sum is σ = 1620995050080. Its totient is φ = 864530690688.
The previous prime is 1212530025631. The next prime is 1212530025691. The reversal of 1212530025655 is 5565200352121.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1212530025655 is a prime.
It is a super-2 number, since 2×12125300256552 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 321624117 + ... + 321627886.
It is an arithmetic number, because the mean of its divisors is an integer number (101312190630).
Almost surely, 21212530025655 is an apocalyptic number.
1212530025655 is a deficient number, since it is larger than the sum of its proper divisors (408465024425).
1212530025655 is a wasteful number, since it uses less digits than its factorization.
1212530025655 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 643252050.
The product of its (nonzero) digits is 90000, while the sum is 37.
Adding to 1212530025655 its reverse (5565200352121), we get a palindrome (6777730377776).
The spelling of 1212530025655 in words is "one trillion, two hundred twelve billion, five hundred thirty million, twenty-five thousand, six hundred fifty-five".
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