Base | Representation |
---|---|
bin | 10110100110000000… |
… | …10100001110100111 |
3 | 1011022100202100120111 |
4 | 23103000110032213 |
5 | 144320240310043 |
6 | 5323352113451 |
7 | 606410245465 |
oct | 132300241647 |
9 | 34270670514 |
10 | 12130010023 |
11 | 516509007a |
12 | 2426395887 |
13 | 11b4084a31 |
14 | 830dc1835 |
15 | 4aeda209d |
hex | 2d30143a7 |
12130010023 has 4 divisors (see below), whose sum is σ = 12425863968. Its totient is φ = 11834156080.
The previous prime is 12130009999. The next prime is 12130010027. The reversal of 12130010023 is 32001003121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12130010023 - 29 = 12130009511 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12130009985 and 12130010012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12130010027) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147926911 + ... + 147926992.
It is an arithmetic number, because the mean of its divisors is an integer number (3106465992).
Almost surely, 212130010023 is an apocalyptic number.
12130010023 is a deficient number, since it is larger than the sum of its proper divisors (295853945).
12130010023 is an equidigital number, since it uses as much as digits as its factorization.
12130010023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 295853944.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 12130010023 its reverse (32001003121), we get a palindrome (44131013144).
The spelling of 12130010023 in words is "twelve billion, one hundred thirty million, ten thousand, twenty-three".
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