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12130012113 = 323175797277
BaseRepresentation
bin10110100110000000…
…10100101111010001
31011022100202110102220
423103000110233101
5144320240341423
65323352131253
7606410254542
oct132300245721
934270673386
1012130012113
1151650916aa
122426396b29
1311b408597b
14830dc24c9
154aeda29e3
hex2d3014bd1

12130012113 has 8 divisors (see below), whose sum is σ = 16876538688. Its totient is φ = 7735080144.

The previous prime is 12130012051. The next prime is 12130012157. The reversal of 12130012113 is 31121003121.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12130012113 - 220 = 12128963537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12130012092 and 12130012101.

It is not an unprimeable number, because it can be changed into a prime (12130012163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 87898570 + ... + 87898707.

It is an arithmetic number, because the mean of its divisors is an integer number (2109567336).

Almost surely, 212130012113 is an apocalyptic number.

It is an amenable number.

12130012113 is a deficient number, since it is larger than the sum of its proper divisors (4746526575).

12130012113 is a wasteful number, since it uses less digits than its factorization.

12130012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175797303.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 12130012113 its reverse (31121003121), we get a palindrome (43251015234).

The spelling of 12130012113 in words is "twelve billion, one hundred thirty million, twelve thousand, one hundred thirteen".

Divisors: 1 3 23 69 175797277 527391831 4043337371 12130012113