Base | Representation |
---|---|
bin | 11011100101001001100010… |
… | …101100111011110011100111 |
3 | 120220111011211002021222210210 |
4 | 123211021202230323303213 |
5 | 111344340122303220403 |
6 | 1105552301254150503 |
7 | 34356434052442116 |
oct | 3345114254736347 |
9 | 526434732258723 |
10 | 121300122320103 |
11 | 357171028422a1 |
12 | 11730939652433 |
13 | 528b72498106c |
14 | 21d4d58979c7d |
15 | e0546418db03 |
hex | 6e5262b3bce7 |
121300122320103 has 16 divisors (see below), whose sum is σ = 165792398188032. Its totient is φ = 78840015960000.
The previous prime is 121300122320081. The next prime is 121300122320137. The reversal of 121300122320103 is 301023221003121.
It is not a de Polignac number, because 121300122320103 - 213 = 121300122311911 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 121300122320103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121300122320203) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 339649183 + ... + 340006128.
It is an arithmetic number, because the mean of its divisors is an integer number (10362024886752).
Almost surely, 2121300122320103 is an apocalyptic number.
121300122320103 is a deficient number, since it is larger than the sum of its proper divisors (44492275867929).
121300122320103 is a wasteful number, since it uses less digits than its factorization.
121300122320103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 679656806.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 121300122320103 its reverse (301023221003121), we get a palindrome (422323343323224).
The spelling of 121300122320103 in words is "one hundred twenty-one trillion, three hundred billion, one hundred twenty-two million, three hundred twenty thousand, one hundred three".
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