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121300232111 = 304139888271
BaseRepresentation
bin111000011111000001…
…1101010011110101111
3102121002121210020122022
41300332003222132233
53441410324411421
6131420300540355
711522634650402
oct1607603523657
9377077706568
10121300232111
1147496900813
121b6132516bb
13b5916a3b96
145c29cc7d39
15324e1de7ab
hex1c3e0ea7af

121300232111 has 4 divisors (see below), whose sum is σ = 121340123424. Its totient is φ = 121260340800.

The previous prime is 121300232101. The next prime is 121300232159. The reversal of 121300232111 is 111232003121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121300232111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 121300232111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121300232101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19941095 + ... + 19947176.

It is an arithmetic number, because the mean of its divisors is an integer number (30335030856).

Almost surely, 2121300232111 is an apocalyptic number.

121300232111 is a deficient number, since it is larger than the sum of its proper divisors (39891313).

121300232111 is an equidigital number, since it uses as much as digits as its factorization.

121300232111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39891312.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 121300232111 its reverse (111232003121), we get a palindrome (232532235232).

The spelling of 121300232111 in words is "one hundred twenty-one billion, three hundred million, two hundred thirty-two thousand, one hundred eleven".

Divisors: 1 3041 39888271 121300232111