12130035 has 16 divisors (see below), whose sum is σ = 19643904. Its totient is φ = 6390752.

The previous prime is 12130007. The next prime is 12130049. The reversal of 12130035 is 53003121.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 12130035 - 2⁵ = 12130003 is a prime.

It is a super-3 number, since 3×12130035³ (a number of 22 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 12129996 and 12130023.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3627 + ... + 6116.

It is an arithmetic number, because the mean of its divisors is an integer number (1227744).

Almost surely, 2^12130035 is an apocalyptic number.

12130035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12130035 is a deficient number, since it is larger than the sum of its proper divisors (7513869).

12130035 is an equidigital number, since it uses as much as digits as its factorization.

12130035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9834.

The product of its (nonzero) digits is 90, while the sum is 15.

The square root of 12130035 is about 3482.8199781212. The cubic root of 12130035 is about 229.7668399609.

Adding to 12130035 its reverse (53003121), we get a palindrome (65133156).

The spelling of 12130035 in words is "twelve million, one hundred thirty thousand, thirty-five".