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12130043101 = 111102731191
BaseRepresentation
bin10110100110000000…
…11100010011011101
31011022100211000221121
423103000130103131
5144320242334401
65323352530541
7606410444101
oct132300342335
934270730847
1012130043101
115165102a10
1224263b0a51
1311b4096ac7
14830dcd901
154aedabca1
hex2d301c4dd

12130043101 has 4 divisors (see below), whose sum is σ = 13232774304. Its totient is φ = 11027311900.

The previous prime is 12130043047. The next prime is 12130043147. The reversal of 12130043101 is 10134003121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12130043101 - 27 = 12130042973 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12130043171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 551365585 + ... + 551365606.

It is an arithmetic number, because the mean of its divisors is an integer number (3308193576).

Almost surely, 212130043101 is an apocalyptic number.

12130043101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

12130043101 is a deficient number, since it is larger than the sum of its proper divisors (1102731203).

12130043101 is a wasteful number, since it uses less digits than its factorization.

12130043101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1102731202.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12130043101 its reverse (10134003121), we get a palindrome (22264046222).

The spelling of 12130043101 in words is "twelve billion, one hundred thirty million, forty-three thousand, one hundred one".

Divisors: 1 11 1102731191 12130043101