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121301001303 = 340433667101
BaseRepresentation
bin111000011111000011…
…0100110010001010111
3102121002200020022202220
41300332012212101113
53441411024020203
6131420325233423
711522644333056
oct1607606462127
9377080208686
10121301001303
1147497286709
121b613562873
13b5918b3021
145c2a04839d
15324e2e2653
hex1c3e1a6457

121301001303 has 4 divisors (see below), whose sum is σ = 161734668408. Its totient is φ = 80867334200.

The previous prime is 121301001281. The next prime is 121301001319. The reversal of 121301001303 is 303100103121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121301001303 - 214 = 121300984919 is a prime.

It is a super-2 number, since 2×1213010013032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121301001373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20216833548 + ... + 20216833553.

It is an arithmetic number, because the mean of its divisors is an integer number (40433667102).

Almost surely, 2121301001303 is an apocalyptic number.

121301001303 is a deficient number, since it is larger than the sum of its proper divisors (40433667105).

121301001303 is an equidigital number, since it uses as much as digits as its factorization.

121301001303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40433667104.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 121301001303 its reverse (303100103121), we get a palindrome (424401104424).

The spelling of 121301001303 in words is "one hundred twenty-one billion, three hundred one million, one thousand, three hundred three".

Divisors: 1 3 40433667101 121301001303