Base | Representation |
---|---|
bin | 10001101001101110010… |
… | …011101100011100010011 |
3 | 11021222001020122112210021 |
4 | 101221232103230130103 |
5 | 124333242021342003 |
6 | 2325131533244311 |
7 | 153432023031004 |
oct | 21515623543423 |
9 | 4258036575707 |
10 | 1213031434003 |
11 | 428497691364 |
12 | 177115933697 |
13 | 8a5083442bc |
14 | 429d51171ab |
15 | 21848c9b2bd |
hex | 11a6e4ec713 |
1213031434003 has 4 divisors (see below), whose sum is σ = 1214498220120. Its totient is φ = 1211564647888.
The previous prime is 1213031434001. The next prime is 1213031434049. The reversal of 1213031434003 is 3004341303121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1213031434003 - 21 = 1213031434001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1213031434001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 733391818 + ... + 733393471.
It is an arithmetic number, because the mean of its divisors is an integer number (303624555030).
Almost surely, 21213031434003 is an apocalyptic number.
1213031434003 is a deficient number, since it is larger than the sum of its proper divisors (1466786117).
1213031434003 is an equidigital number, since it uses as much as digits as its factorization.
1213031434003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1466786116.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1213031434003 its reverse (3004341303121), we get a palindrome (4217372737124).
The spelling of 1213031434003 in words is "one trillion, two hundred thirteen billion, thirty-one million, four hundred thirty-four thousand, three".
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