Base | Representation |
---|---|
bin | 1011000010000101110100… |
… | …1100111110000111100011 |
3 | 1120221200001222102120100110 |
4 | 2300201131030332013203 |
5 | 3042221332114401110 |
6 | 41444410502022403 |
7 | 2361255240660564 |
oct | 260413514760743 |
9 | 46850058376313 |
10 | 12130551325155 |
11 | 39575a0a8675a |
12 | 143ab95117a03 |
13 | 69cba1879b03 |
14 | 2dd19c3a016b |
15 | 160824389a20 |
hex | b085d33e1e3 |
12130551325155 has 64 divisors (see below), whose sum is σ = 20694018723840. Its totient is φ = 6050160510336.
The previous prime is 12130551325141. The next prime is 12130551325177. The reversal of 12130551325155 is 55152315503121.
12130551325155 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12130551325155 - 239 = 11580795511267 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 27862474 + ... + 28294496.
It is an arithmetic number, because the mean of its divisors is an integer number (323344042560).
Almost surely, 212130551325155 is an apocalyptic number.
12130551325155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12130551325155 is a deficient number, since it is larger than the sum of its proper divisors (8563467398685).
12130551325155 is a wasteful number, since it uses less digits than its factorization.
12130551325155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 433320.
The product of its (nonzero) digits is 112500, while the sum is 39.
Adding to 12130551325155 its reverse (55152315503121), we get a palindrome (67282866828276).
The spelling of 12130551325155 in words is "twelve trillion, one hundred thirty billion, five hundred fifty-one million, three hundred twenty-five thousand, one hundred fifty-five".
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