Search a number
-
+
12131030143 = 31391323553
BaseRepresentation
bin10110100110001000…
…01101010001111111
31011022102200011220201
423103010031101333
5144321020431033
65323430024331
7606422024551
oct132304152177
934272604821
1012131030143
115165717551
1224267a80a7
1311b435115b
148311a94d1
154b000447d
hex2d310d47f

12131030143 has 4 divisors (see below), whose sum is σ = 12522353728. Its totient is φ = 11739706560.

The previous prime is 12131030077. The next prime is 12131030159. The reversal of 12131030143 is 34103013121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12131030143 - 217 = 12130899071 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12131030143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12131030243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195661746 + ... + 195661807.

It is an arithmetic number, because the mean of its divisors is an integer number (3130588432).

Almost surely, 212131030143 is an apocalyptic number.

12131030143 is a deficient number, since it is larger than the sum of its proper divisors (391323585).

12131030143 is an equidigital number, since it uses as much as digits as its factorization.

12131030143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 391323584.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12131030143 its reverse (34103013121), we get a palindrome (46234043264).

The spelling of 12131030143 in words is "twelve billion, one hundred thirty-one million, thirty thousand, one hundred forty-three".

Divisors: 1 31 391323553 12131030143