Base | Representation |
---|---|
bin | 10001101001110010100… |
… | …101011101011101100111 |
3 | 11021222020020200122100222 |
4 | 101221302211131131213 |
5 | 124333413404400403 |
6 | 2325143015354555 |
7 | 153433554031424 |
oct | 21516245353547 |
9 | 4258206618328 |
10 | 1213103200103 |
11 | 428524149293 |
12 | 177135982a5b |
13 | 8a51a180952 |
14 | 42a00878d4b |
15 | 21850225338 |
hex | 11a7295d767 |
1213103200103 has 4 divisors (see below), whose sum is σ = 1213884337008. Its totient is φ = 1212322063200.
The previous prime is 1213103200097. The next prime is 1213103200121. The reversal of 1213103200103 is 3010023013121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1213103200103 - 24 = 1213103200087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1213103200403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 390566123 + ... + 390569228.
It is an arithmetic number, because the mean of its divisors is an integer number (303471084252).
Almost surely, 21213103200103 is an apocalyptic number.
1213103200103 is a deficient number, since it is larger than the sum of its proper divisors (781136905).
1213103200103 is an equidigital number, since it uses as much as digits as its factorization.
1213103200103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 781136904.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 1213103200103 its reverse (3010023013121), we get a palindrome (4223126213224).
The spelling of 1213103200103 in words is "one trillion, two hundred thirteen billion, one hundred three million, two hundred thousand, one hundred three".
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