Base | Representation |
---|---|
bin | 10001101001110011001… |
… | …000001011011100001010 |
3 | 11021222020212211000220011 |
4 | 101221303020023130022 |
5 | 124333423222120242 |
6 | 2325143542422134 |
7 | 153434024265535 |
oct | 21516310133412 |
9 | 4258225730804 |
10 | 1213112301322 |
11 | 4285292a5159 |
12 | 177138a3194a |
13 | 8a51c01939c |
14 | 42a01b67a1c |
15 | 21850e21d17 |
hex | 11a7320b70a |
1213112301322 has 4 divisors (see below), whose sum is σ = 1819668451986. Its totient is φ = 606556150660.
The previous prime is 1213112301307. The next prime is 1213112301337. The reversal of 1213112301322 is 2231032113121.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (1213112301307) and next prime (1213112301337).
It can be written as a sum of positive squares in only one way, i.e., 934878205881 + 278234095441 = 966891^2 + 527479^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1213112301293 and 1213112301302.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 303278075329 + ... + 303278075332.
Almost surely, 21213112301322 is an apocalyptic number.
1213112301322 is a deficient number, since it is larger than the sum of its proper divisors (606556150664).
1213112301322 is an equidigital number, since it uses as much as digits as its factorization.
1213112301322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 606556150663.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1213112301322 its reverse (2231032113121), we get a palindrome (3444144414443).
The spelling of 1213112301322 in words is "one trillion, two hundred thirteen billion, one hundred twelve million, three hundred one thousand, three hundred twenty-two".
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