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1213113011122 = 2606556505561
BaseRepresentation
bin10001101001110011001…
…010111000101110110010
311021222020221011002120001
4101221303022320232302
5124333423412323442
62325144005540214
7153434033313115
oct21516312705662
94258227132501
101213113011122
1142852973a471
1217713911466a
138a51c20749c
1442a01cb057c
15218510122b7
hex11a732b8bb2

1213113011122 has 4 divisors (see below), whose sum is σ = 1819669516686. Its totient is φ = 606556505560.

The previous prime is 1213113011111. The next prime is 1213113011129. The reversal of 1213113011122 is 2211103113121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1033819199361 + 179293811761 = 1016769^2 + 423431^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 1213113011122.

It is not an unprimeable number, because it can be changed into a prime (1213113011129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 303278252779 + ... + 303278252782.

Almost surely, 21213113011122 is an apocalyptic number.

1213113011122 is a deficient number, since it is larger than the sum of its proper divisors (606556505564).

1213113011122 is an equidigital number, since it uses as much as digits as its factorization.

1213113011122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 606556505563.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1213113011122 its reverse (2211103113121), we get a palindrome (3424216124243).

The spelling of 1213113011122 in words is "one trillion, two hundred thirteen billion, one hundred thirteen million, eleven thousand, one hundred twenty-two".

Divisors: 1 2 606556505561 1213113011122