Base | Representation |
---|---|
bin | 10001101001110011110… |
… | …110011010001100110001 |
3 | 11021222021201121202010221 |
4 | 101221303312122030301 |
5 | 124333434322423101 |
6 | 2325145054253041 |
7 | 153434232302245 |
oct | 21516366321461 |
9 | 4258251552127 |
10 | 1213124420401 |
11 | 428535122423 |
12 | 177140ab7181 |
13 | 8a5216a063a |
14 | 42a03600425 |
15 | 21852017aa1 |
hex | 11a73d9a331 |
1213124420401 has 4 divisors (see below), whose sum is σ = 1213131269952. Its totient is φ = 1213117570852.
The previous prime is 1213124420393. The next prime is 1213124420461. The reversal of 1213124420401 is 1040244213121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1213124420401 - 23 = 1213124420393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1213124420461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3151861 + ... + 3515746.
It is an arithmetic number, because the mean of its divisors is an integer number (303282817488).
Almost surely, 21213124420401 is an apocalyptic number.
It is an amenable number.
1213124420401 is a deficient number, since it is larger than the sum of its proper divisors (6849551).
1213124420401 is an equidigital number, since it uses as much as digits as its factorization.
1213124420401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6849550.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1213124420401 its reverse (1040244213121), we get a palindrome (2253368633522).
The spelling of 1213124420401 in words is "one trillion, two hundred thirteen billion, one hundred twenty-four million, four hundred twenty thousand, four hundred one".
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