Base | Representation |
---|---|
bin | 10001101001110100001… |
… | …100010010010011100011 |
3 | 11021222022010102002212012 |
4 | 101221310030102103203 |
5 | 124333442304431420 |
6 | 2325145421223135 |
7 | 153434332116005 |
oct | 21516414222343 |
9 | 4258263362765 |
10 | 1213130155235 |
11 | 42853838a059 |
12 | 177142a01aab |
13 | 8a52292aa2b |
14 | 42a04294375 |
15 | 2185279bdc5 |
hex | 11a743124e3 |
1213130155235 has 4 divisors (see below), whose sum is σ = 1455756186288. Its totient is φ = 970504124184.
The previous prime is 1213130155231. The next prime is 1213130155249. The reversal of 1213130155235 is 5325510313121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1213130155235 - 22 = 1213130155231 is a prime.
It is a super-3 number, since 3×12131301552353 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1213130155231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121313015519 + ... + 121313015528.
It is an arithmetic number, because the mean of its divisors is an integer number (363939046572).
Almost surely, 21213130155235 is an apocalyptic number.
1213130155235 is a deficient number, since it is larger than the sum of its proper divisors (242626031053).
1213130155235 is an equidigital number, since it uses as much as digits as its factorization.
1213130155235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 242626031052.
The product of its (nonzero) digits is 13500, while the sum is 32.
Adding to 1213130155235 its reverse (5325510313121), we get a palindrome (6538640468356).
The spelling of 1213130155235 in words is "one trillion, two hundred thirteen billion, one hundred thirty million, one hundred fifty-five thousand, two hundred thirty-five".
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