Base | Representation |
---|---|
bin | 11011100101010101111010… |
… | …000111010001101101101001 |
3 | 120220112110002102121012012001 |
4 | 123211111322013101231221 |
5 | 111400044320400102213 |
6 | 1110002335005051001 |
7 | 34360414100051131 |
oct | 3345257207215551 |
9 | 526473072535161 |
10 | 121313400003433 |
11 | 357217a6739300 |
12 | 11733424256a61 |
13 | 528ca5c738b11 |
14 | 21d5858149ac1 |
15 | e0598eb921dd |
hex | 6e557a1d1b69 |
121313400003433 has 6 divisors (see below), whose sum is σ = 133344480995642. Its totient is φ = 110284909093920.
The previous prime is 121313400003427. The next prime is 121313400003437. The reversal of 121313400003433 is 334300004313121.
It can be written as a sum of positive squares in only one way, i.e., 92300655226329 + 29012744777104 = 9607323^2 + 5386348^2 .
It is not a de Polignac number, because 121313400003433 - 229 = 121312863132521 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (121313400003437) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 501295041216 + ... + 501295041457.
Almost surely, 2121313400003433 is an apocalyptic number.
It is an amenable number.
121313400003433 is a deficient number, since it is larger than the sum of its proper divisors (12031080992209).
121313400003433 is a wasteful number, since it uses less digits than its factorization.
121313400003433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1002590082695 (or 1002590082684 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 121313400003433 its reverse (334300004313121), we get a palindrome (455613404316554).
The spelling of 121313400003433 in words is "one hundred twenty-one trillion, three hundred thirteen billion, four hundred million, three thousand, four hundred thirty-three".
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