Base | Representation |
---|---|
bin | 11011100101010101111010… |
… | …000111010001101101100011 |
3 | 120220112110002102121012011211 |
4 | 123211111322013101231203 |
5 | 111400044320400102202 |
6 | 1110002335005050551 |
7 | 34360414100051122 |
oct | 3345257207215543 |
9 | 526473072535154 |
10 | 121313400003427 |
11 | 357217a67392a5 |
12 | 11733424256a57 |
13 | 528ca5c738b08 |
14 | 21d5858149ab9 |
15 | e0598eb921d7 |
hex | 6e557a1d1b63 |
121313400003427 has 2 divisors, whose sum is σ = 121313400003428. Its totient is φ = 121313400003426.
The previous prime is 121313400003377. The next prime is 121313400003437. The reversal of 121313400003427 is 724300004313121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121313400003427 is a prime.
It is a super-2 number, since 2×1213134000034272 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121313400003437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60656700001713 + 60656700001714.
It is an arithmetic number, because the mean of its divisors is an integer number (60656700001714).
Almost surely, 2121313400003427 is an apocalyptic number.
121313400003427 is a deficient number, since it is larger than the sum of its proper divisors (1).
121313400003427 is an equidigital number, since it uses as much as digits as its factorization.
121313400003427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 121313400003427 its reverse (724300004313121), we get a palindrome (845613404316548).
The spelling of 121313400003427 in words is "one hundred twenty-one trillion, three hundred thirteen billion, four hundred million, three thousand, four hundred twenty-seven".
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