Base | Representation |
---|---|
bin | 1011000010001000110011… |
… | …0011110010011100100011 |
3 | 1120221202010122022222120122 |
4 | 2300202030303302130203 |
5 | 3042230001101430430 |
6 | 41445022033030455 |
7 | 2361314106601511 |
oct | 260421463623443 |
9 | 46852118288518 |
10 | 12131350030115 |
11 | 39579709125a8 |
12 | 143b1786b542b |
13 | 69cc9b1983b4 |
14 | 2dd2364ad4b1 |
15 | 16086e557ee5 |
hex | b088ccf2723 |
12131350030115 has 8 divisors (see below), whose sum is σ = 14896169339568. Its totient is φ = 9479380488480.
The previous prime is 12131350030087. The next prime is 12131350030133. The reversal of 12131350030115 is 51103005313121.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12131350030115 - 222 = 12131345835811 is a prime.
It is a super-2 number, since 2×121313500301152 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28212441716 + ... + 28212442145.
It is an arithmetic number, because the mean of its divisors is an integer number (1862021167446).
Almost surely, 212131350030115 is an apocalyptic number.
12131350030115 is a deficient number, since it is larger than the sum of its proper divisors (2764819309453).
12131350030115 is an equidigital number, since it uses as much as digits as its factorization.
12131350030115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56424883909.
The product of its (nonzero) digits is 1350, while the sum is 26.
Adding to 12131350030115 its reverse (51103005313121), we get a palindrome (63234355343236).
The spelling of 12131350030115 in words is "twelve trillion, one hundred thirty-one billion, three hundred fifty million, thirty thousand, one hundred fifteen".
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