Base | Representation |
---|---|
bin | 111000011111011100… |
… | …0011001000110011011 |
3 | 102121010120210111110200 |
4 | 1300332320121012123 |
5 | 3441422344221210 |
6 | 131421513113243 |
7 | 11523163310151 |
oct | 1607670310633 |
9 | 377116714420 |
10 | 121314054555 |
11 | 474a3691821 |
12 | 1b6179b8823 |
13 | b594503545 |
14 | 5c2ba853d1 |
15 | 32505200c0 |
hex | 1c3ee1919b |
121314054555 has 24 divisors (see below), whose sum is σ = 210521420928. Its totient is φ = 64625836416.
The previous prime is 121314054551. The next prime is 121314054557. The reversal of 121314054555 is 555450413121.
121314054555 is a `hidden beast` number, since 1 + 2 + 13 + 1 + 40 + 54 + 555 = 666.
It is not a de Polignac number, because 121314054555 - 22 = 121314054551 is a prime.
It is not an unprimeable number, because it can be changed into a prime (121314054551) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1523082 + ... + 1600751.
It is an arithmetic number, because the mean of its divisors is an integer number (8771725872).
Almost surely, 2121314054555 is an apocalyptic number.
121314054555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
121314054555 is a deficient number, since it is larger than the sum of its proper divisors (89207366373).
121314054555 is a wasteful number, since it uses less digits than its factorization.
121314054555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3124707 (or 3124704 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 36.
Adding to 121314054555 its reverse (555450413121), we get a palindrome (676764467676).
The spelling of 121314054555 in words is "one hundred twenty-one billion, three hundred fourteen million, fifty-four thousand, five hundred fifty-five".
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