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12132031413 = 34044010471
BaseRepresentation
bin10110100110010000…
…00001101110110101
31011022111120001101210
423103020001232311
5144321300001123
65323503312033
7606433364655
oct132310015665
934274501353
1012132031413
115166240847
122426bab619
1311b4611b18
1483138a365
154b0150e93
hex2d3201bb5

12132031413 has 4 divisors (see below), whose sum is σ = 16176041888. Its totient is φ = 8088020940.

The previous prime is 12132031363. The next prime is 12132031441. The reversal of 12132031413 is 31413023121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12132031413 - 213 = 12132023221 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12132031413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12132031213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2022005233 + ... + 2022005238.

It is an arithmetic number, because the mean of its divisors is an integer number (4044010472).

Almost surely, 212132031413 is an apocalyptic number.

It is an amenable number.

12132031413 is a deficient number, since it is larger than the sum of its proper divisors (4044010475).

12132031413 is an equidigital number, since it uses as much as digits as its factorization.

12132031413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4044010474.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 12132031413 its reverse (31413023121), we get a palindrome (43545054534).

The spelling of 12132031413 in words is "twelve billion, one hundred thirty-two million, thirty-one thousand, four hundred thirteen".

Divisors: 1 3 4044010471 12132031413