Base | Representation |
---|---|
bin | 10001101001111010001… |
… | …101011010001110100011 |
3 | 11021222120011101022001020 |
4 | 101221322031122032203 |
5 | 124334144131104443 |
6 | 2325203425140523 |
7 | 153436666210611 |
oct | 21517215321643 |
9 | 4258504338036 |
10 | 1213231113123 |
11 | 42858a375227 |
12 | 17717078a743 |
13 | 8a53a818523 |
14 | 42a138546b1 |
15 | 2185b590583 |
hex | 11a7a35a3a3 |
1213231113123 has 4 divisors (see below), whose sum is σ = 1617641484168. Its totient is φ = 808820742080.
The previous prime is 1213231113103. The next prime is 1213231113137. The reversal of 1213231113123 is 3213111323121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1213231113123 - 229 = 1212694242211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1213231113093 and 1213231113102.
It is not an unprimeable number, because it can be changed into a prime (1213231113103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202205185518 + ... + 202205185523.
It is an arithmetic number, because the mean of its divisors is an integer number (404410371042).
Almost surely, 21213231113123 is an apocalyptic number.
1213231113123 is a deficient number, since it is larger than the sum of its proper divisors (404410371045).
1213231113123 is an equidigital number, since it uses as much as digits as its factorization.
1213231113123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 404410371044.
The product of its digits is 648, while the sum is 24.
Adding to 1213231113123 its reverse (3213111323121), we get a palindrome (4426342436244).
The spelling of 1213231113123 in words is "one trillion, two hundred thirteen billion, two hundred thirty-one million, one hundred thirteen thousand, one hundred twenty-three".
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