12132413300113 has 4 divisors (see below), whose sum is σ = 12770961368560. Its totient is φ = 11493865231668.

The previous prime is 12132413300089. The next prime is 12132413300123. The reversal of 12132413300113 is 31100331423121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12132413300113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12132413300123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 319274034195 + ... + 319274034232.

It is an arithmetic number, because the mean of its divisors is an integer number (3192740342140).

Almost surely, 2^{12132413300113} is an apocalyptic number.

It is an amenable number.

12132413300113 is a deficient number, since it is larger than the sum of its proper divisors (638548068447).

12132413300113 is an equidigital number, since it uses as much as digits as its factorization.

12132413300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 638548068446.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 12132413300113 its reverse (31100331423121), we get a palindrome (43232744723234).

The spelling of 12132413300113 in words is "twelve trillion, one hundred thirty-two billion, four hundred thirteen million, three hundred thousand, one hundred thirteen".