12133011000000 has 784 divisors, whose sum is σ = 43944929997696. Its totient is φ = 2929920000000.

The previous prime is 12133010999957. The next prime is 12133011000049. The reversal of 12133011000000 is 11033121.

12133011000000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×12133011000000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 12133011000000.

It is an unprimeable number.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 11120999455 + ... + 11121000545.

Almost surely, 2^{12133011000000} is an apocalyptic number.

12133011000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12133011000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21972464998848).

12133011000000 is an abundant number, since it is smaller than the sum of its proper divisors (31811918997696).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12133011000000 is an equidigital number, since it uses as much as digits as its factorization.

12133011000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1484 (or 1449 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 12133011000000 its reverse (11033121), we get a palindrome (12133022033121).

The spelling of 12133011000000 in words is "twelve trillion, one hundred thirty-three billion, eleven million", and thus it is an aban number.