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1213301202023 = 3732791924379
BaseRepresentation
bin10001101001111110011…
…000110001110001100111
311021222202001021011221102
4101221332120301301213
5124334320101431043
62325214411310315
7153441510024461
oct21517630616147
94258661234842
101213301202023
11428615997039
1217719014b39b
138a54c1b8651
1442a1cc9b131
15218627d76b8
hex11a7e631c67

1213301202023 has 4 divisors (see below), whose sum is σ = 1246093126440. Its totient is φ = 1180509277608.

The previous prime is 1213301202017. The next prime is 1213301202037. The reversal of 1213301202023 is 3202021033121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1213301202023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1213301201986 and 1213301202004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213301202073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16395962153 + ... + 16395962226.

It is an arithmetic number, because the mean of its divisors is an integer number (311523281610).

Almost surely, 21213301202023 is an apocalyptic number.

1213301202023 is a deficient number, since it is larger than the sum of its proper divisors (32791924417).

1213301202023 is an equidigital number, since it uses as much as digits as its factorization.

1213301202023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32791924416.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1213301202023 its reverse (3202021033121), we get a palindrome (4415322235144).

The spelling of 1213301202023 in words is "one trillion, two hundred thirteen billion, three hundred one million, two hundred two thousand, twenty-three".

Divisors: 1 37 32791924379 1213301202023