12133021525441 has 4 divisors (see below), whose sum is σ = 12134845223892. Its totient is φ = 12131197826992.

The previous prime is 12133021525421. The next prime is 12133021525489. The reversal of 12133021525441 is 14452512033121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2027590884225 + 10105430641216 = 1423935^2 + 3178904^2 .

It is a cyclic number.

It is not a de Polignac number, because 12133021525441 - 2¹⁵ = 12133021492673 is a prime.

It is a super-2 number, since 2×12133021525441² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12133021525397 and 12133021525406.

It is not an unprimeable number, because it can be changed into a prime (12133021525411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 911839246 + ... + 911852551.

It is an arithmetic number, because the mean of its divisors is an integer number (3033711305973).

Almost surely, 2^{12133021525441} is an apocalyptic number.

It is an amenable number.

12133021525441 is a deficient number, since it is larger than the sum of its proper divisors (1823698451).

12133021525441 is an equidigital number, since it uses as much as digits as its factorization.

12133021525441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1823698450.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 12133021525441 its reverse (14452512033121), we get a palindrome (26585533558562).

The spelling of 12133021525441 in words is "twelve trillion, one hundred thirty-three billion, twenty-one million, five hundred twenty-five thousand, four hundred forty-one".