12133032433 has 4 divisors (see below), whose sum is σ = 12524420608. Its totient is φ = 11741644260.

The previous prime is 12133032419. The next prime is 12133032437. The reversal of 12133032433 is 33423033121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33423033121 = 1223 ⋅27328727.

It is a cyclic number.

It is not a de Polignac number, because 12133032433 - 2²¹ = 12130935281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12133032398 and 12133032407.

It is not an unprimeable number, because it can be changed into a prime (12133032437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195694041 + ... + 195694102.

It is an arithmetic number, because the mean of its divisors is an integer number (3131105152).

Almost surely, 2^12133032433 is an apocalyptic number.

It is an amenable number.

12133032433 is a deficient number, since it is larger than the sum of its proper divisors (391388175).

12133032433 is an equidigital number, since it uses as much as digits as its factorization.

12133032433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 391388174.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 12133032433 its reverse (33423033121), we get a palindrome (45556065554).

The spelling of 12133032433 in words is "twelve billion, one hundred thirty-three million, thirty-two thousand, four hundred thirty-three".