Base | Representation |
---|---|
bin | 10110100110010111… |
… | …10110010111100001 |
3 | 1011022120102221220221 |
4 | 23103023312113201 |
5 | 144322024032231 |
6 | 5323541003041 |
7 | 606445040224 |
oct | 132313662741 |
9 | 34276387827 |
10 | 12133033441 |
11 | 5166865671 |
12 | 24273b3481 |
13 | 11b48a2c39 |
14 | 83156b5bb |
15 | 4b029cd11 |
hex | 2d32f65e1 |
12133033441 has 4 divisors (see below), whose sum is σ = 12179166912. Its totient is φ = 12086899972.
The previous prime is 12133033421. The next prime is 12133033447. The reversal of 12133033441 is 14433033121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14433033121 = 13 ⋅1110233317.
It is a cyclic number.
It is not a de Polignac number, because 12133033441 - 233 = 3543098849 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12133033447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23066341 + ... + 23066866.
It is an arithmetic number, because the mean of its divisors is an integer number (3044791728).
Almost surely, 212133033441 is an apocalyptic number.
It is an amenable number.
12133033441 is a deficient number, since it is larger than the sum of its proper divisors (46133471).
12133033441 is an equidigital number, since it uses as much as digits as its factorization.
12133033441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46133470.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 12133033441 its reverse (14433033121), we get a palindrome (26566066562).
The spelling of 12133033441 in words is "twelve billion, one hundred thirty-three million, thirty-three thousand, four hundred forty-one".
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