Base | Representation |
---|---|
bin | 1011000010001111101111… |
… | …0011110100111100000111 |
3 | 1120221220221102112200002222 |
4 | 2300203323303310330013 |
5 | 3042242304322430203 |
6 | 41445530520122555 |
7 | 2361411211663646 |
oct | 260437363647407 |
9 | 46856842480088 |
10 | 12133212311303 |
11 | 3958737045a66 |
12 | 143b5b830645b |
13 | 6a0206c53825 |
14 | 2dd37195935d |
15 | 16092ccb5038 |
hex | b08fbcf4f07 |
12133212311303 has 4 divisors (see below), whose sum is σ = 12166272835680. Its totient is φ = 12100151786928.
The previous prime is 12133212311299. The next prime is 12133212311323. The reversal of 12133212311303 is 30311321233121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12133212311303 - 22 = 12133212311299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12133212311323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16530261638 + ... + 16530262371.
It is an arithmetic number, because the mean of its divisors is an integer number (3041568208920).
Almost surely, 212133212311303 is an apocalyptic number.
12133212311303 is a deficient number, since it is larger than the sum of its proper divisors (33060524377).
12133212311303 is an equidigital number, since it uses as much as digits as its factorization.
12133212311303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33060524376.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 12133212311303 its reverse (30311321233121), we get a palindrome (42444533544424).
The spelling of 12133212311303 in words is "twelve trillion, one hundred thirty-three billion, two hundred twelve million, three hundred eleven thousand, three hundred three".
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